ASCP MLT(ASCP) ASCP-MLT

TestPDF 的 ASCP ASCP-MLT題庫是由頂級IT專家團隊以最高技術水平整理製作的，確保了試題的準確性和專業性。這些IT團隊成員都是來自指定認證專家、培訓師和 ASCP 相關工作從業者，他們對 ASCP-MLT考試內容和 MLT(ASCP) 認證要求的資歷瞭如指掌，這樣可以確保 ASCP-MLT題庫的高質量。

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1、不需要大量的時間金錢，僅需20-30個小時，自學成才，輕鬆通過ASCP ASCP-MLT考試。
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3、根據ASCP ASCP-MLT的考試科目不斷的變化，採取不斷的更新，會提供最新的考試內容。
4、在互聯網上提供24小時客戶服務。
5、根據過去的題庫問題及答案，TestPDF提供的ASCP ASCP-MLT考試題庫和真實的考試有緊密的相似性。
6、通過了ASCP認證ASCP-MLT考試在工作上會有很大的晉升機會，使用了TestPDF提供的測試軟體，你會成功的更快。
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最新的 MLT(ASCP) ASCP-MLT 免費考試真題:

1. Haemophilus influenzae is both X and V factor dependent for growth, and is the most common cause of obstructive laryngitis and epiglottitis. H. parainfluenzae is only V-factor dependent and causes only mild pharyngitis, rarely obstructive in nature. H. aphrophilus can be part of the normal upper respiratory flora in humans, does not cause pharyngitis, and is not X or V-factor dependent for growth. Although H. haemolyticus is both X and V-factor dependent, it is beta hemolytic on blood agar and is generally considered non pathogenic.
Acute obstructive epiglottitis, both in adults and children, is caused by the bacterial species shown in this split screen photograph. The colonies recovered on chocolate agar (upper frame) required both hematin and NAD, (as shown by colony growth only between the X and V strips in the lower frame). The most likely identification is:

A) Haemophilus parainfluenzae
B) Haemophilus haemolyticus
C) Haemophilus influenzae
D) Haemophilus aphrophilus

2. Calculation:
Cells Counted (in this case the average of both sides) X dilution factor (in this case 100) / # of squares counted (in this case 9) X area of each square (1mm2) X 0.1mm (depth factor) So, in this problem:
158 x 100 / 9 x 1 x 0.1mm = 17555.55/mm3 (can be converted to 17.5 x 109/L*)
*There are 1,000,000 mm3 in a liter (L). So 17555.55 X 1,000,000 = 17.5 x 109/L A manual white blood cell count was performed by the hematology technologist. The cell counts for both sides were 152 and 164 respectively. All nine large squares were counted on each side. The dilution for this kit was pre-measured at 1:100. What should the technologist report as the white cell count?

A) 1.75 x 10^9/L
B) 17.5 x 10^9/L
C) 177.5 x 10^9/L
D) 175 x 10^9/L

3. Secondary granules, also known as specific granules first appear in the myelocyte stage next to the nucleus. In neutrophils this is termed the "dawn of neutrophilia".
What is one of the main characteristics of secondary granules in the neutrophilic granulocyte cytoplasm?

A) Appear first at the myelocyte stage
B) Dissolve in mature granulocytes
C) Are derived from azurophil (primary) granules
D) Are formed on the mitochondria

4. S. aureus does not have capsular material as a defense mechanism. H. influenzae, K. pneumoniae, N.
meningitidis, and S. pneumoniae each have capsular material use as a defense mechanism. This capsular material is an antiphagocytic substance which helps deter bacterial death by macrophages and other white blood cells.
Microbiology
Which one of the following does NOT have capsular material as a defense mechanism?

A) H. influenzae
B) K. pneumoniae
C) S. aureus
D) S. pneumoniae
E) N. meningitidis

5. HbsAg is positive in acute and chronic Hepatitis B infections, since the antigen is found on the actual surface of the virus. HbeAg is present in the blood when the hepatitis B viruses are replicating, indicating an active infection. Anti-Hbc IgM is present due to the immune response to the presence of the hepatitis core antigen and indicates an acute infection. Anti-HBs is generally interpreted as indicating recovery and immunity from hepatitis B virus infection, according to the CDC.
Given the following results, what is the immune status of the patient?
HbsAg: positive
HbeAg: positive
Anti-HBc IgM: positive
Anti-HBs: negative

A) immunization
B) chronic infection
C) susceptible
D) acute infection

問題與答案：